It is note that 8% of Kaplan students are left handed. If 20 (TWENTY) students are randomly selected, calculate the
i. probablility that none of them are left-handed,
ii. probability that at most 2 are left-handed,
Prob of none left handed: 0.92^20
Prob exactly 1 left handed: 0.08*(0.92^19)*20 (20 because there are 20 ways of choosing the 1)
Prob exactly 2 left handed: (0.08^2)*(0.92^18)*190. (190 because there are ncr(20,2) = 190 ways of choosing a pair)
Sum the three probabilities above to get the probability of "at most" 2.