IT question: How to calculate time for second delay to merge two tones in one channel?
I think like that:
a = 300 (Hz)
b = 600 (Hz)
length = 3000 (milliseconds)
I should mix them in one sound but using only 1 channel, for example of device with one channel - PC-Speaker!
Then, we need to use this:
Pseudo-C code
tone.generate(a);
delay(length div (2 div 2 * (a div 2)));
tone.stop();
tone.generate(b);
delay(length div (2 div 2 * (a div 2)));
Is it true or not? Whatever should I do to synth it IN ONE CHANNEL?
Best regards,
Gabriel Mattraws.
