Show that the equation 3x2 - x3 + 3 = 0 can be rearranged to give x = 3 + 3/x2
3x^2 - x^3 + 3 = 0 Subtract 3 from both sides
3x^2 - x^3 = -3 Multiply both sides by -1
x^3 - 3x^2 = 3 Factor out x^2
x^2 (x-3) = 3 Divide both sides by x^2
x-3 = 3/(x^2) Add 3 to both sides
x=3+ 3/(x^2)