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Ive tried to enter the calculation in a calculator

 

asin(35.4)(sin(51)/31.2)

 

why do i get an error??

Guest May 29, 2017
 #1
avatar+7096 
+2

Since the trigonometric functions are based on a unit circle,

it can't tell you what the arcsin of 35.4 is.

 

You can only take the arcsin of a value between -1 and 1 (including -1 and 1).

hectictar  May 29, 2017
 #2
avatar+92625 
+2

I would not say that trigonometric functions are based on the unit circle but it is certainly true that 

asin(x) only is defined (has a value)   for    

\(-1\le x\le1\)

Melody  May 29, 2017

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