wut is this
(s^2t^-3)^5/6(s^6)^2
assuming s is a variable this would be the indefinite integral.
\(\int\frac{s^22}{6t^15}\;ds=\frac{s^23}{138t^15}+C\)
\(\Large\frac{(s^{2t^{-3}})^5}{6(s^6)^2}=\frac{s^{-30t}}{6s^{12}}=\frac{1}{6s^{12}\times s^{30t}}=\frac{1}{6s^{30t+12}}\)
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+123 
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