John invests a total of $4,500 in two accounts paying 10% and 3% simple interest, respectively. How much was invested in each account if, after one year, the

Call the amount in one acct  [ doesn't matter which one], x

Call the amount in the other acct   4500 - x    and we have

.10x  + .03(4500 - x)  = 205     simplify

.10x + 135  - .03.x   = 205

.07x + 135  = 205     subtract 135 from both sides

.07x =  70       divide boh sides by  .07

x = $1000  this was the amount in the 10% account

So  4500 - 1000  = $3500  = the amount in the 3% acct

You have way too much time on your hands CPhill