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Johnnys Riverboat Tours sends their tour boat along the Mississippi River where the current is running at 3 miles per hous. If the tour boat travels 36 miles up stream in the same time it takes to travel 62 miles downstream, what is the speed of the tour boat in still water? It neeeds an equation

 Apr 27, 2015

Best Answer 

 #1
avatar+23246 
+8

Let  b  represent the speed of the boat in still water.

The boat's speed downstream will be  b + 3.

The boat's speed upstream will be b - 3.

Distance = rate x time

Upstream:  36  =  (b - 3)(t)                       where  t  represents the time.

Downstream:  62  =  (b + 3)(t)                  same time upsteam as downstream

Solving the top equation for t:  36/(b - 3)  =  t

Solving the second equation:    62/(b + 3)  =  t

Since they both equal t, the equal each other:  36/(b - 3)  =  62/(b + 3)

Cross-multiplying:  36(b + 3)  =  62(b - 3)

Simplifying:           36b + 108  =  62b - 186

Simpligying:                    108  =  26b - 186

Simplifying:                     294  =  26b

Dividing:                              b  =  11.3 mph (approximately)

 Apr 27, 2015
 #1
avatar+23246 
+8
Best Answer

Let  b  represent the speed of the boat in still water.

The boat's speed downstream will be  b + 3.

The boat's speed upstream will be b - 3.

Distance = rate x time

Upstream:  36  =  (b - 3)(t)                       where  t  represents the time.

Downstream:  62  =  (b + 3)(t)                  same time upsteam as downstream

Solving the top equation for t:  36/(b - 3)  =  t

Solving the second equation:    62/(b + 3)  =  t

Since they both equal t, the equal each other:  36/(b - 3)  =  62/(b + 3)

Cross-multiplying:  36(b + 3)  =  62(b - 3)

Simplifying:           36b + 108  =  62b - 186

Simpligying:                    108  =  26b - 186

Simplifying:                     294  =  26b

Dividing:                              b  =  11.3 mph (approximately)

geno3141 Apr 27, 2015

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