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x^4-20x^2+64 ..can you find the x please
 Sep 5, 2013
 #1
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x^4-20x^2+64 = 0, y = x^2 => y^2 - 20y + 64 = 0 => y1 = 16, y2 = 4 --> x^2 = 16 --> x = +-4. x^2 = 4 --> x = +-2

solve(x^4-20x^2+64 = 0, x)
 Sep 5, 2013

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