K= 1/2(6.6*10 ^2 kg)(2.11*10^4m/s)^2
I need it in Scientific Notation and I need the units along with it. Thank you in advance
K= 1/2(6.6*10 ^2 kg)(2.11*10^4m/s)^2
\(\begin{array}{|rcll|} \hline K &=& \frac12*(6.6*10 ^2 kg)*(2.11*10^4\frac{m}{s})^2 \\ K &=& \frac12*6.6*10 ^2 kg * (2.11*10^4\frac{m}{s})^2 \\ K &=& \frac12*6.6*10 ^2 kg * 2.11^2*10^8\frac{m^2}{s^2} \\ K &=& \frac12*6.6*10 ^2 * 2.11^2*10^8\frac{ kg * m^2}{s^2} \\ K &=& \frac12*6.6 * 2.11^2*10^{10} \frac{ kg * m^2}{s^2} \\ K &=& 14.69193 *10^{10} \frac{ kg * m^2}{s^2} \\ K &=& 1.469193 *10^{11} \frac{ kg * m}{s^2} \cdot m \qquad | \qquad 1~N = 1~\frac{kg*m}{s^2} \\ \mathbf{K} &\mathbf{=}& \mathbf{1.469193 *10^{11} N \cdot m} \\ \hline \end{array} \)
K= 1/2(6.6*10 ^2 kg)(2.11*10^4m/s)^2
\(\begin{array}{|rcll|} \hline K &=& \frac12*(6.6*10 ^2 kg)*(2.11*10^4\frac{m}{s})^2 \\ K &=& \frac12*6.6*10 ^2 kg * (2.11*10^4\frac{m}{s})^2 \\ K &=& \frac12*6.6*10 ^2 kg * 2.11^2*10^8\frac{m^2}{s^2} \\ K &=& \frac12*6.6*10 ^2 * 2.11^2*10^8\frac{ kg * m^2}{s^2} \\ K &=& \frac12*6.6 * 2.11^2*10^{10} \frac{ kg * m^2}{s^2} \\ K &=& 14.69193 *10^{10} \frac{ kg * m^2}{s^2} \\ K &=& 1.469193 *10^{11} \frac{ kg * m}{s^2} \cdot m \qquad | \qquad 1~N = 1~\frac{kg*m}{s^2} \\ \mathbf{K} &\mathbf{=}& \mathbf{1.469193 *10^{11} N \cdot m} \\ \hline \end{array} \)