keplers law

F = Gm1m2/r2     G = gravitational constant = 6.67 × 10-11 N-m2/kg2

So let's plug in the numbers

6.67x 10^-11   x   1 x10^6  x 75 x 10^6  / (1 x10^3)^2   

= 500.25 x 10^(-11+6+6-6) = 500.25 x 10^-5 N

What is the gravitational force of attraction of two asteroids that have a mass of 1,000,000kg and 75,000,000kg if they are 1000m apart?

\(F=G\frac{m_1\times m_2}{r2}\)

\(G=6.672\times10^{-11}\times\frac{m^3}{kg\times s^2}\)

\(\large F=6.672\times10^{-11}\times\frac{m^3}{kg\times s^2}\times\frac{10^6kg\times 75\times10^6kg}{10^6m^2}\)

\(F=0.005004\frac{mkg}{s^2} [N]\)

  !