Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes then nickels,how many coins does he has altogether
n = nickels value = 5n
d = dimes = n-34 value = 10(n-34) summed = 485
5n + 10(n-34) = 485
5n + 10n - 340 = 485
15n = 825
n = 55 nickels 55-34=21 dimes 21+ 55 = 76 coins total
n = nickels value = 5n
d = dimes = n-34 value = 10(n-34) summed = 485
5n + 10(n-34) = 485
5n + 10n - 340 = 485
15n = 825
n = 55 nickels 55-34=21 dimes 21+ 55 = 76 coins total