+0  
 
0
42
3
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If $f(x)$ is a monic quartic polynomial such that $f(-1)=-1$, $f(2)=-4$, $f(-3)=-9$, and $f(4)=-16$, find $f(1)$.

 Jan 10, 2021
 #1
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0

We can use the finite difference method:

 

f(-1) f(2) f(-3) f(4) f(1)

-1 -4 -9 -16 -1

-3 -5 -7 15

-2 -2 22

0 24

24

 

Therefore f(1) = -1.

 Jan 10, 2021
 #2
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Can you please elaborate on your solution?

 

how does 24 made f(-1)=1?

 Jan 10, 2021
edited by Guest  Jan 10, 2021
 #3
avatar+31514 
+2

I get the following

 Jan 10, 2021

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