A ball initially rolling at 10 m/s comes to a stop in 25 seconds. Assuming the ball has uniform acceleration, how far does it travel during this time interval?
a = 10 m/s / 25 s
then the displacement will be vi t + 1/2 a t2 = distance
vi = initial velocity (10 m/s) a = acceleration t = time (25 s) I'll let you do the 'plug and chug'
+36915 
