+0  
 
0
747
1
avatar
(4) Consider the variable x taking the following values:
3,8,1,5,4,3.
Find ∑6i=1(xi−6)2.

The following ``answers'' have been proposed for part (c).
(a) 0,
(b) 52,
(c) 144,
(d) −12
(e) None of the above.
 Aug 31, 2013
 #1
avatar+104 
0
i=1: (3-6)*2 = -6
i=2: (8-6)*2 = 4
i=3: (1-6)*2 = -10
i=4: (5-6)*2 = -2
i=5: (4-6)*2 = -4
i=6: (3-6)*2 = -6

=> -6 + 4 -10 -2 -4 -6 = -24
 Aug 31, 2013

0 Online Users