#1**+1 **

If you start with what you're given 5x^{2} + 19x + 16 > 20

Subtract 20 from both sides 5x^{2} + 19x – 4 > 0

Factor the left side (5x – 1)(x + 4) > 0

I thought I I'd figure out the answer as I went,

but I find that I don't know what to do now.

.

Guest Jul 26, 2019

#2**0 **

Building on Guest's answer (Thanx!)

Between x = -4 and + 1/5 the graph is neg or zero

Below -4 or above +1/5 it is > 0

so (-inf,-4) U (1/5, + inf) it is greater than zero (or the original equation is > 20)

EDIT: So NOT satisfied would be [-4,1/5] -4, -3,-2,-1 0 FIVE integer values

ElectricPavlov Jul 26, 2019

edited by
ElectricPavlov
Jul 26, 2019

edited by ElectricPavlov Jul 26, 2019

edited by ElectricPavlov Jul 26, 2019

edited by ElectricPavlov Jul 26, 2019

edited by ElectricPavlov Jul 26, 2019