We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
108
2
avatar

For how many integer values of x is \(5x^{2}+19x+16 > 20\) not satisfied?

 Jul 26, 2019
 #1
avatar
+1

 

If you start with what you're given    5x2 + 19x + 16  > 20

 

Subtract 20 from both sides             5x2 + 19x – 4  > 0 

 

Factor the left side                           (5x – 1)(x + 4)  > 0 

 

I thought I I'd figure out the answer as I went,

but I find that I don't know what to do now.

.

 Jul 26, 2019
 #2
avatar+19749 
+2

Building on Guest's answer  (Thanx!)

 

Between x = -4 and + 1/5   the graph is neg   or zero  

 

Below -4   or above +1/5 it is > 0

 

so    (-inf,-4) U (1/5, + inf)    it is greater than zero  (or the original equation is > 20)

 

EDIT:   So NOT satisfied would be     [-4,1/5]    -4, -3,-2,-1 0    FIVE integer values

 Jul 26, 2019
edited by ElectricPavlov  Jul 26, 2019
edited by ElectricPavlov  Jul 26, 2019
edited by ElectricPavlov  Jul 26, 2019

23 Online Users

avatar