+0  
 
0
84
7
avatar+464 

Thank you in advance for helping me solve this. Can I please get it today before 6:30 pm if possible please!

 

shreyas1  Oct 8, 2018
 #1
avatar+94110 
0

CPhill will help you but I am less likely to.

So far you have NEVER said thank you to anyone on any of your threads! 

Saying thank you in advance is nice but it is not the same as a proper thank you after the help is actually given.

 

Also:

The point system is also design for askers, and other, to show their appreciation of the time and effort that the answerer has dedicated to the question. I am not sure if you ever give people a point but I know that you usually don't.

 

Also:

Answerers are trying to teach and also maybe to practice their own skills. They are not interested in your time scale. 

It is a total discouragement to me when someone says an answer must be done by a set time, it suggests that a timely answer, for homework or a test perhaps is of far more interest than learning how to answer the question.

 

I have not given up on you otherwise I would not be bothering to write all this. I will now watch and see if your behaviour is amended.

Melody  Oct 8, 2018
 #2
avatar+464 
+1

Sorry, I forgot my manners. I will try to keep up with it from now. Thank you for reminding me of my manners.

shreyas1  Oct 8, 2018
 #3
avatar+94110 
0

You can go back and fix all your past ommisions. 

You can access all your old post by clicking on your username.  (that is how I discovered that you never say thankyou)

Melody  Oct 8, 2018
 #4
avatar+464 
+1

I have already started doing that. Thank you and sorry again.

shreyas1  Oct 8, 2018
 #5
avatar+464 
+1

Done, sorry about the Time limit as well

shreyas1  Oct 8, 2018
 #6
avatar+92759 
+1

Triangles AZY and  ACY have the same height

But base AC is 5/2  of base AZ..so area of ACY  = (5/2) AZY

 

Similary....triangles ZYC and  AZY  have the same height

But base ZC is  (3/2) base AZ...so  area of ZYC  = (3/2) AZY

 

And triangles ACY  and  YBC  have the same  height

But base AY is 3 times base  BY....so area of ACY = (3)YBC

 

So.....

 

ACY  = (3)YBC    (1)

ACY = (5/2)AZY  (2)

ZYC = (3/2)AZY    (3)

 

From (1)  and (2)

(3)YBC = (5/2)AZY

(6/5)YBC  = AZY    (4)

 

And from (3)

(2/3)ZYC  = AZY  (5)

 

So...from  (4)  and (5)

 

(6/5)YBC =  (2 / 3)  ZYC

 

So

 

[ YBC ] / [ ZYC ]  =    [  2/3] / [ 6/5]

 

[ YBC] / [ZYC ] =  (2/3) * (5/6)   =  10/ 18  =  5 / 9

 

 

cool  cool  cool

CPhill  Oct 9, 2018
 #7
avatar+464 
0

Thank you so much CPhill, you helped me solve my homework in time

shreyas1  Oct 9, 2018

18 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.