what is the measure of the largest angle of a triangle who has side lengths of 6, 7, and 11?
Go online to this link and have all your three angles solved there, using their special calculator:
http://www.calculatorsoup.com/calculators/geometry-plane/triangle-theorems.php
using the law: c^2=a^2+b^2-2ab*cos(angle)
so, 11^2=6^2+7^2-(2*6*7)*cos x
121=36+49-84*cos x
120=cos x
cos x = -1/2
sketch the triangle.
Remember that the longest side is opposite the biggest angle and vise verse.
Use the cosine rule
