In ΔFGH, f = 60 cm, g = 10 cm and h=62 cm. Find the measure of ∠F to the nearest degree.
cos (F) = (h^2 + g^2 - f^2) / 2hg = (3844 + 100 - 3600) / 1240 = 43 / 155
F = cos$^-1$(43 / 155)$^\circ$ ≈ $\boxed{74^\circ}$
+592 
