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Find AB where CB=29, CA=13, and M<C=41
Guest Feb 8, 2012
 #1
avatar+310 
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What does M have to do with it? is "M

if thats right, then according to the law of cosines 

(AB)2=(CB)2+(CA)2-2(CB)*(CA)*(cos(M 2+13 2-2*29*13*cos(41)=440.948976511858

(AB)2=440.948976511858

AB=(440.948976511858)1/2=20.9987851199029607

 

therefore AB=20.9987851199029607

Ehrlich  Mar 26, 2017

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