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a=6 b=10 and Angle Measure C is 110 degrees, I need to complete the triangle using laws of cosine and sine

Guest Mar 6, 2017
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Using the Law of cosines to find  "c"......we have

 

c = sqrt [6^2 + 10^2 - 2(6)(10) cos (110) ]  ≈ 13.3

 

Using the Law of Sines to find angle A, we have

 

sinA / 6   =  sin(110) / 13.3

 

sinA  = 6sin(110)/13.3

 

arcsin (6sin (110) / 13.3)  = A  ≈ 25.08°

 

Angle B  =   180 - 110 - 25.08  = 44.92°

 

And "b"  =

 

b/sin(44.92) = 13.3/sin(110)

 

b = 13.3*sin(44.92)/ sin(110) ≈ 10

 

a = 6            b  = 10           c = 13.3

A = 25.08    B = 44.92       C = 110

 

 

cool cool cool

CPhill  Mar 6, 2017

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