In ΔQRS, r = 940 inches, q = 790 inches and ∠Q=23°. Find all possible values of ∠R, to the nearest degree.
Last one, sorry! Thank you CPhill for the help with my previous one!
sin R / r = sin Q / q
sin R / 940 = sin 23 / 790
sin R = 940 sin 23 / 790
arcsin [ 940 sin 23 / 790 ] = R = 27.7°
Second possibility for R = 180 - 27.7 = 152.3°
152.3 + 23 = 175.3 < 180......so....a second triangle exists
