Find AC.
Hello Guest!
Law of cosines:
\((7\sqrt{3} )^2=9^2+x^2-2\cdot9\cdot x\cdot cos\ 150°\\ x^2-cos\ 150°\cdot18x+81-147=0\\ x=cos\ 150°\cdot 9\pm \sqrt{81\cdot cos^2\ 150°+147}\\ x=-7.79423\pm \sqrt{207.75}\\ x\in \{{\color{blue}6.6193},-22.207\}\)
\(\color{blue}\overline{AC}=6.6193\)
!