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Let a and b be numbers such that a^3=5 and b^3=4. Find the value of (ab^2)^{-3}.

 Nov 24, 2022
 #1
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(ab^2)^{-3} = 16/5

 Nov 24, 2022
 #2
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a^3 ==5, solve for a

 

a ==1.71

 

b^3 ==4, solve for b

 

b=1.587

 

{ [1.71*1.587]^2 }^ - 3 =={0.00250358}

 Nov 25, 2022

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