Let a be a real number for which there exists a unique value of b such that the quadratic equation x^2 + 2bx + (a-b) = 0 has one real soluti

Let a be a real number for which there exists a unique value of b such that the quadratic equation x^2 + 2bx + (a-b) = 0 has one real solution. Find a.

Hello Guest!

a=b

\(x^2 + 2bx + (a-b) = 0 \\ x^2 + 2bx + (b-b) = 0 \\ x^2+2bx=0\\ x(x+2b)=0 \)

\(x_1=0\\ x_2=-2b\)

  !