Let AB be a diameter of a circle centered at O. Let E be a point on the circle, and let the tangent at B intersect the tangent at E and AE at C and D, respectively. If angle BAE = 41 degrees, find angle CED, in degrees.
Angels BAE, CBE, and BEC are congruent.
angle CED = 90 - 41
Since BE and EC are tangents drawn from C, they are equal
And since BAE = 41.....then CBE = 41
And minor arc BE = 82
Then CEB equals half of this = 41
But AEB = 90 since A and B are diameter endpoints
So CED = 180 -90 - 41 = 90 - 41 = 49°
