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Let ABCD be a parallelogram. If AC = 9 and BD = 17, then find AB^2 + BC^2.

 May 22, 2022
 #1
avatar+117494 
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Let ABCD be a parallelogram. If AC = 9 and BD = 17, then find AB^2 + BC^2.

 

\(BC^2=4.5^2+8.5^2-(2*4.5*8.5*cos\alpha) \qquad (1)\\~\\ AB^2=4.5^2+8.5^2-(2*4.5*8.5*cos(180-\alpha))\\ AB^2=4.5^2+8.5^2+(2*4.5*8.5*cos(\alpha))\qquad (2)\\ (1)+(2)=\)

 

You can check and finish it 

 May 23, 2022
 #2
avatar+117494 
+1

Do you repost because you are too lazy to finish it yourself? 

 

https://web2.0calc.com/questions/still-stuck

 

To ignore an answer and then repost is the height of rudeness.

 May 24, 2022
edited by Melody  May 24, 2022

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