+0  
 
0
1305
1
avatar

let θ be an angle in quadrant ii such that =cosθ−4/9. find the exact values of CSCθ and COTθ

 

CSCθ = 

 

COTθ = 

 Oct 8, 2020
 #1
avatar+36916 
+1

Remember      cos^2 + sin^2 = 1

                             so sin = +- sqrt (65) / 9     but since it is in Q II   it is + sqrt(65)/ 9

then:

CSC = 1/sin

Cot = cos/ sin

 Oct 8, 2020

6 Online Users

avatar
avatar
avatar