Let 𝜃 be an angle in quadrant II such that tan 𝜃 = −47. Find sin 𝜃 and sec

In Q2, y  will be positive and x will be negative

tan (theta)  = y  / x  =   47 /  -1

r  =sqrt  ( x^2 + y^2)  =  sqrt   [  (-1)^2  +  47^2  ] =  sqrt [ 2210 ] 

sin (theta)    = y/r  =  47  /sqrt (2210)  = 47 sqrt (2210)  /2210

sec (theta)  =  r/x  =  sqrt (2210)  / -1  =    -sqrt (2210)