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Let C be the circle with equation \(x^2-6y-3=-y^2-4x\). If (a,b) is the center of C$ and r is its radius, what is the value of a+b+r?

 Oct 9, 2019

Best Answer 

 #1
avatar+22096 
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Let's put the circle in standard form  

 

x^2 + 4x +y^2 -6y = 3    now 'complete the square'on x and y

(x+2)*2 + (y-3)^2 = 3  +4+9

(x+2)^2 + (y-3)^2 = 4^2           so the center   is  (a,b) = (-2,3)   and the radius is 4       a+b+r = 5

 Oct 9, 2019
 #1
avatar+22096 
0
Best Answer

Let's put the circle in standard form  

 

x^2 + 4x +y^2 -6y = 3    now 'complete the square'on x and y

(x+2)*2 + (y-3)^2 = 3  +4+9

(x+2)^2 + (y-3)^2 = 4^2           so the center   is  (a,b) = (-2,3)   and the radius is 4       a+b+r = 5

ElectricPavlov Oct 9, 2019

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