Let f(2)=-4 and f'(2)=5. Then the equation of the tangent line to the graph of y=f(x) at x=2 is y=?

f (2)  = - 4         f  ' (2)  = 5

So......the equation of the tangent line at x =  2   is given by  :

y - (-4)  = 5(x - 2)

y + 4  = 5x -10

y  = 5x - 14