+0  
 
0
46
1
avatar

Let f(x) = Ax - 2B^2 and g(x) = 2Bx, where B is nonzero.  If f(g(1)) = 0, what is A in terms of B?

 Oct 27, 2020
 #1
avatar+28021 
+1

g(1) = 2 Bx  =  2B

f (g(1)) =   f (2B) =   A (2B) - 2B^2       and we are told this = 0

                                   2B^2 = A (2B)

                                   2 B^2 /2B = A

                                     A = B

 Oct 27, 2020

26 Online Users

avatar
avatar
avatar