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# Let$f(x) = \begin{cases} k(x) &\text{if }x>3, \\ x^2-6x+12&\text{if }x\leq3. \end{cases}$

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Let $$f(x) = \begin{cases} k(x) &\text{if }x>3, \\ x^2-6x+12&\text{if }x\leq3. \end{cases}$$Find the function $$k(x)$$ such that $$f$$ is its own inverse.

Tysm!!!

Jul 10, 2022

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Since we want f(x) to be its own inverse, f(x) = x^2 - 6x + 12.

Jul 10, 2022
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So what is $$k(x)$$?

Guest Jul 10, 2022