Let f(x)= x^6 + 6 x^5 - 36 x^4 - 210 x^3 + 375 x^2 + 1500 x - 2500. In factored form f(x)= (x-2)^2 (x+5)^3 (x-5). What are the zeros of this function? If there is more than one zero, list your answer as a list of numbers separated by commas such as: 2,3,4
(x-2)^2 (x+5)^3 (x-5)
The zeroes are the x values that make each thing in the respective parentheses = 0
So ... we have x = 2, x= -5 and x = 5
Here's the graph.....https://www.desmos.com/calculator/utjkaiwltp
(x-2)^2 (x+5)^3 (x-5)
The zeroes are the x values that make each thing in the respective parentheses = 0
So ... we have x = 2, x= -5 and x = 5
Here's the graph.....https://www.desmos.com/calculator/utjkaiwltp