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Let f(x)= x^6 + 6 x^5 - 36 x^4 - 210 x^3 + 375 x^2 + 1500 x - 2500. In factored form f(x)= (x-2)^2 (x+5)^3 (x-5). What are the zeros of this function? If there is more than one zero, list your answer as a list of numbers separated by commas such as: 2,3,4

 May 19, 2015

Best Answer 

 #1
avatar+129839 
+5

(x-2)^2 (x+5)^3 (x-5)

 

The zeroes are the x values that make each thing in the respective parentheses  = 0

 

So ... we have  x = 2, x= -5 and x = 5

 

Here's the graph.....https://www.desmos.com/calculator/utjkaiwltp

 

 

 May 19, 2015
 #1
avatar+129839 
+5
Best Answer

(x-2)^2 (x+5)^3 (x-5)

 

The zeroes are the x values that make each thing in the respective parentheses  = 0

 

So ... we have  x = 2, x= -5 and x = 5

 

Here's the graph.....https://www.desmos.com/calculator/utjkaiwltp

 

 

CPhill May 19, 2015

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