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Let g(n) be the product of the proper positive integer divisors of n. (Recall that a proper divisor of n is a divisor other than n.) For how many values of n does n not divide g(n), given that \(2 \le n \le 50\)?

 Aug 5, 2016

Best Answer 

 #1
avatar+129840 
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Let g(n) be the product of the proper positive integer divisors of n. (Recall that a proper divisor of n is a divisor other than n.) For how many values of n does n not divide g(n), given that  2 ≤ n ≤ 50?

 

I think I understand this one.........

 

All the n"s  ≥ 2 and  ≤  25  will divide at least one n  from 2 to 50 inclusive...so each of these will divide g(n)

 

And all the composite n's > 25  but  ≤ 50  can be divided by at least two n's  from 2 to 25 inclusive

 

But the primes from 25 to 50 cannot be formed by any other factors than 1 and themselves

 

Thus, the "n"s"   that will not divide g(n)  will be all the primes > 25   and  < 50 

 

And these are   29, 31, 37, 41, 43, 47

 

 

cool cool cool


 

 Aug 5, 2016
 #1
avatar+129840 
0
Best Answer

Let g(n) be the product of the proper positive integer divisors of n. (Recall that a proper divisor of n is a divisor other than n.) For how many values of n does n not divide g(n), given that  2 ≤ n ≤ 50?

 

I think I understand this one.........

 

All the n"s  ≥ 2 and  ≤  25  will divide at least one n  from 2 to 50 inclusive...so each of these will divide g(n)

 

And all the composite n's > 25  but  ≤ 50  can be divided by at least two n's  from 2 to 25 inclusive

 

But the primes from 25 to 50 cannot be formed by any other factors than 1 and themselves

 

Thus, the "n"s"   that will not divide g(n)  will be all the primes > 25   and  < 50 

 

And these are   29, 31, 37, 41, 43, 47

 

 

cool cool cool


 

CPhill Aug 5, 2016
 #2
avatar+48 
0

6 isn't correct :(

TheNewuser  Aug 5, 2016

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