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Let \(f(x)=ax^3+bx^2+cx+d.\) It is given that \(f(1)=4, f(2)=6, f(3)=8\) and \(f(4)=10.\) Find \(f(0).\)

 Oct 16, 2022
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f(0) = -72.

 Oct 16, 2022

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