Let line L1 be the graph of5x+8y=-9. Line l2 is perpendicular to line L1 and passes through the point (10,10).

If line L2 is the graph of the equation y=mx+b, then find m+b.

TETSER
Nov 5, 2018

#1**+2 **

5x+8y= -9

8y = -5x-9

y= -5/8 x - 9/5 slope = m = -5/8

Perpindicular slope = 8/5

L2 y = 8/5 x + b

10 = 8/5 (10) + b

b = -6

L2 y = 8/5 x -6 m+ b = 8/5 - 6 = -22/5

ElectricPavlov
Nov 5, 2018