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Let line \(l_1\) be the graph of \(5x + 8y = -9\). Line \(l_2\) is perpendicular to line \(l_1\) and passes through the point (10,10). If line \(l_2\) is the graph of the equation y=mx+b, then find m+b.

 Aug 20, 2019
 #1
avatar+104647 
+2

L1   =  5x + 8y   = - 9

 

In the form     Ax + By   = C......the slope of this line   =  -A/B

 

So....the slope of L1   =    -5 /8

 

So....the slope of perpendicular L2   =     8/5

 

So..... using the point (10,10)....the equation of L2  is

 

y  = (8/5) (x - 10) + 10    simplify

 

y = (8/5)x  - 16 + 10

 

y = (8/5)x  - 6

 

m = 8/5    and b  = -6

 

So....m + b  =   8/5  - 6  =   8/5  - 30/5     =     -22/5 

 

 

cool cool cool

 Aug 21, 2019
 #2
avatar+8778 
+1

smiley            

 Aug 26, 2019
edited by Guest  Aug 26, 2019

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