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Let f be a function such that f(x+y) = x + f(y) for any two real numbers x and y. If f(0) = 2, then what is f(2012)?

 Nov 6, 2014

Best Answer 

 #4
avatar+105634 
+10

I just realised that I could have done this more easily

 

f(2012+0)=2012+f(0)

f(2012)=2012+2

f(2012)=2014       

 Nov 9, 2014
 #1
avatar+105634 
+10

Umm Interesting    

 

What if x=-2012 and y=2012

f(-2012+2012)=-2012+f(2012)=2

so

-2012+f(2012)=2

f(2012)=2+2012=2014

 

I think that is it :)

 Nov 7, 2014
 #2
avatar+104855 
+5

Very nice, Melody.....I'd have no idea how to approach this one !!!!

 

 Nov 7, 2014
 #3
avatar+105634 
+5

Thanks Chris.

I had to think about it for a while myself.

You can get some really weird questions that are like this one!

 Nov 8, 2014
 #4
avatar+105634 
+10
Best Answer

I just realised that I could have done this more easily

 

f(2012+0)=2012+f(0)

f(2012)=2012+2

f(2012)=2014       

Melody Nov 9, 2014

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