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Let P be a variable point on the parabola \(y^2 = 2x\), and Let B and C be points on the y-axis so that the circle \((x - 1)^2 + y^2 = 1\) is inscribed in triangle PBC. Find the minimum area of triangle PBC.

 Nov 23, 2020
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Quadratic formula: root of ax^2 + bx + c = 0 is x = (-b pm sqrt(b^2 - 4ac))/2a

 

Minimum area of triangle PBC is 12.

 Dec 12, 2020

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