Let P be the point (0,5), let Q be the point (6,9), and let R be the point (10,0). Determine the area of triangle PQR.
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\(A=6\cdot 5+\frac{6\cdot (9-5)}{2}+\frac{(10-6)\cdot 9}{2}-\frac{10\cdot 5}{2}\)
\(A=30+12+18-25\)
\(A=35\)
The area of triangle PQR is 35.
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