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Let p(x) = 2x^3  - 113 and let q be the inverse of p. Find q(137).


Thanks so much :D

WhichWitchIsWhich  Nov 7, 2017
 #1
avatar+92785 
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 p(x) = 2x^3  - 113

 

Let  p(x)  =  y

 

 y = 2x^3  - 113       add 113 to both sides

 

y + 113  =  2x^3     dviide both sides by 2

 

[   y + 113 ]  / 2  =  x^3        take the cube root of both sides

 

∛  (  [   y + 113 ]  / 2 )  =  x        swap x and y

 

∛  (  [   x + 113 ]  / 2 )  =  y  =   q

 

So q (137)  =   ∛  (  [   137 + 113 ]  / 2 )    =  ∛[ 250 / 2 ]  =      ∛ 125  =    5

 

 

cool cool cool

CPhill  Nov 7, 2017

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