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Let P(x) = 4x^3 - 2x^2 + 7x - 1, and let Q(x) = P(x)^2. What is the y-intercept of Q(x)?

 Aug 19, 2016
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Q(x) = [P(x)]2     and     P(x)  =  4x3 - 2x2 + 7x - 1

--->     Q(x)  =  [ 4x3 - 2x2 + 7x - 1 ]2

 

The y-intercept occurs when the x-value is 0; so to find the y-intercept of Q(x) substitute 0 for x:

--->     Q(0)  =  [ 4(0)3 - 2(0)2 + 7(0) - 1 ]2

                      =  [ 0 - 0 + 0 - 1 ]2

                    =  [ -1 ]2

                    =  1

 

So, the y-intercept occurs at (0, 1)

 Aug 19, 2016

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