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Let PQRS be a square with side length 10. The points X and Y lie outside the square such that XQ = 6, XP = 8, YS = 6, and YR = 8. Find XY^2.

 May 13, 2020
edited by Guest  May 13, 2020
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Using right triangles and Pythagoras, we get that XY^2 = 412.

 May 13, 2020

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