Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$
r + s = -4, (r + s)^2 = 16, r^2 + s^2 = 16 - 12 = 4.
Can you please explain how you got that answer? Where did you get -4 from?
+49 
