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Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$

 Apr 12, 2020
 #1
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-1

r + s = -4, (r + s)^2 = 16, r^2 + s^2 = 16 - 12 = 4.

 Apr 12, 2020
 #2
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Can you please explain how you got that answer? Where did you get -4 from?

 Apr 12, 2020

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