Let's play mini-Sudoku!
We wish to place an "X" in four boxes, such that there is exactly one "X" in each row, column, and 2x2 outlined box. For example:
In how many ways can we do this?
Please explain very well in this quesiton.
+118608 I think this is it
1) there are 4 choices for the first row, the X can go anywhere. Just put your X in
2) There are only 2 choices for the next row because it cannot go in the same box as the first one did.
3) There are 2 choices for the next row because it can go in either box but it cannot go under either of the 2 x's that are already there.
4) There is only one possibility left for the last row
so the number of possibilities is 4*2*2*1=16
+118608 I think this is it
1) there are 4 choices for the first row, the X can go anywhere. Just put your X in
2) There are only 2 choices for the next row because it cannot go in the same box as the first one did.
3) There are 2 choices for the next row because it can go in either box but it cannot go under either of the 2 x's that are already there.
4) There is only one possibility left for the last row
so the number of possibilities is 4*2*2*1=16
