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Let x be a real number such that x^2+7x+12\(\le\)0. Find the largest possible value of x^2 + 5x + 6

 May 14, 2021
 #1
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The maximum value of x^2 + 5x + 6 is 182.

 May 14, 2021
 #2
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hm, incorrect

Guest May 14, 2021
 #3
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Factoring x2 + 7x + 12 ≤ 0, we get (x + 3)(x + 4) ≤ 0, so -4 ≤ x ≤ -3. Probaby not the right way to do it, but I then plugged in -4 and -3 to see which resulted in a higher value, and -4 gets us 16 - 20 + 6 = 2, and -3 gets us 9 - 15 + 6 = 0, so the answer is 2.

 May 22, 2021
edited by justchillin  May 22, 2021

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