Let x be a real number such that x^2+7x+12\(\le\)0. Find the largest possible value of x^2 + 5x + 6
+30 Factoring x2 + 7x + 12 ≤ 0, we get (x + 3)(x + 4) ≤ 0, so -4 ≤ x ≤ -3. Probaby not the right way to do it, but I then plugged in -4 and -3 to see which resulted in a higher value, and -4 gets us 16 - 20 + 6 = 2, and -3 gets us 9 - 15 + 6 = 0, so the answer is 2.
