lim x→2(x²-8x+12)/(x³-3x-2)

Find the following limit:

lim_(x->2) (x^2-8 x+12)/(x^3-3 x-2)

(x^2-8 x+12)/(x^3-3 x-2) = (x-6)/(x+1)^2:

lim_(x->2) (x-6)/(x+1)^2

lim_(x->2) (x-6)/(x+1)^2 = (2-6)/(1+2)^2 = -4/9:

Answer: | -4/9