lim tan5x
x->0 e2x -1
Thanks in advance
x->0 e^(2x) -1 use L'Hospital's Rule
lim 5sec^2(5x) = 5secx^2(0) = 5*1 = 5
x->0 2e^(2x) 2e^(2*0) 2 *1 2
Thanks a lot!