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Solve the limit algebraically. No L'Hôpital's Rule.

 

\(\lim_{x\rightarrow 0} \frac{3sin(4x)}{sin(3x)}\)

zxElementzx  Aug 11, 2018

Best Answer 

 #1
avatar+27133 
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As x→0 sin(ax)→ax, so \(\lim_{x\rightarrow 0}\frac{3sin{4x}}{sin{3x}}\rightarrow\frac{3*4x}{3x}\rightarrow4\)

Alan  Aug 11, 2018
 #1
avatar+27133 
+1
Best Answer

As x→0 sin(ax)→ax, so \(\lim_{x\rightarrow 0}\frac{3sin{4x}}{sin{3x}}\rightarrow\frac{3*4x}{3x}\rightarrow4\)

Alan  Aug 11, 2018

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