I'm not sure how i can show work for this problem: \(\lim_{x\to -6} \frac{-12}{(6+x)^2}\)
Note that as x → -6 from both sides (6 + x)^2 takes on a very small value [ ≈ 0 ]
So
lim -12 -12
x → - 6 ________ = ____ = -∞ [ i.e., the limit does not exist ]
(6 + x)^2 ≈ 0
thanks!
