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I'm not sure how i can show work for this problem:
\(\lim_{x\to -6} \frac{-12}{(6+x)^2}\)

 Sep 9, 2019
 #1
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Note that as  x →  -6  from both sides   (6 + x)^2  takes on a very small value  [ ≈ 0 ]

 

So   

 

lim                      -12                   -12

x → - 6           ________   =      ____  =      -∞      [ i.e., the limit does not exist ]

                       (6 + x)^2              ≈ 0

 

 

cool cool cool

 Sep 9, 2019
edited by CPhill  Sep 9, 2019
 #2
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thanks!

Guest Sep 9, 2019

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